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The initial velocity of a particle of mass 0.1kg is 40 m/s in the direction…

The initial velocity of a particle of mass 0.1kg is 40 m/s in the direction of the unit vector j. The velocity of the particle changed to 30 m/s in the direction of the unit vector i. Find the change in momentum. 

Explanation

u = 40j m/s ; v = 30i m/s,

Change in momentum : (m(v – u))

= (0.1 (30i – 40j))

= (3i – 4j)

Magnitude : (sqrt{3^{2} + 4^{2}})

= (sqrt{25})

= (5 Ns^{-1})