A straight line 2x+3y=6, passes through the point (-1,2). Find the equation of the line.
-
A.
2x-3y=2 -
B.
2x-3y=-2 -
C.
2x+3y=-4 -
D.
2x+3y=4
Correct Answer: Option D
Explanation
(2x+3y = 6 implies 3y = 6-2x)
(y = frac{6}{3} – frac{2x}{3})
Parallel lines have the same gradient
(therefore) Gradient of the line = (frac{-2}{3})
Line passes through (-1,2)
Equation: (frac{y-2}{x-(-1)} = frac{y-2}{x+1} = frac{-2}{3})
(3y-6 = -2x-2 implies 3y+2x = -2+6 =4)