If (f(x) = 2x^{2} – 3x – 1), find the value of x for which f(x) is minimum.

**A.**

(frac{3}{2})**B.**

(frac{4}{3})**C.**

(frac{3}{4})**D.**

(frac{2}{3})

##### Correct Answer: Option C

##### Explanation

(y = 2x^{2} – 3x – 1)

(frac{mathrm d y}{mathrm d x} = 4x – 3 = 0) (At turning point)

(4x = 3 implies x = frac{3}{4})