The polynomial (2x^{3} + x^{2} – 3x + p) has a remainder of 20 when divided by (x – 2). Find the value of constant p.

A.
8 
B.
6 
C.
6 
D.
8
Explanation
Remainder for f(2) = 20.
(f(2) = 2(2^{3}) + 2^{2} – 3(2) + p = 20)
(16 + 4 – 6 + p = 20)
(14 + p = 20)
(p = 6)