The velocity (v ms^{-1}) of a particle moving in a straight line is given by (v = 3t^{2} – 2t + 1) at time t secs. Find the acceleration of the particle after 3 seconds.
-
A.
(26 ms^{-2}) -
B.
(18 ms^{-2}) -
C.
(17 ms^{-2}) -
D.
(16 ms^{-2})
Correct Answer: Option D
Explanation
(v(t) = 3t^{2} – 2t + 1)
(frac{mathrm d v}{mathrm d t} = a(t) = 6t – 2)
(a(3) = 6(3) – 2 = 18 – 2 = 16 ms^{-2})