51 women wore coloured shoes to a party, out of which 21 wore purple and 9 wore white. if a woman is selected at Random. What is the probability that she is wearing neither a purple shoe nor a white shoe?
-
A.
(frac{10}{17}) -
B.
(frac{7}{17}) -
C.
(frac{20}{51}) -
D.
(frac{3}{17}) -
E.
(frac{1}{51})
Correct Answer: Option B
Explanation
No of women wearing both purple and white shoes = 21 + 9
= 30 women.
No of women wearing neither purple nor white shoes = 51 – 30
= 21 women
(therefore) Probability of picking a woman wearing neither purple nor white shoes
= (frac{21}{51})
= (frac{7}{17}).