A bag contains 4 white balls and 6 red balls. Two balls are taken from the bag without replacement. What is the probability that they are both red?
-
A.
(frac{2}{3}) -
B.
(frac{2}{15}) -
C.
(frac{1}{2}) -
D.
(frac{1}{3})
Correct Answer: Option D
Explanation
P(R1) = (frac{6}{10})
= (frac{2}{3})
P(R1 n R11) = P(both red)
(frac{3}{5}) x (frac{5}{9})
= (frac{1}{3})