A chord of a circle subtends an angle of 120° degrees at the centre of a circle of diameter 4√3 cm. Calculate the area of the major sector.
-
A.
4π cm2 -
B.
32 π cm2 -
C.
16 π cm2 -
D.
8 π cm2
Correct Answer: Option D
Explanation
Diameter = 4(sqrt{3}) cm
radius = 2(sqrt{3}) cm
Area of major sector = (frac{theta}{360} times pi r^{2})
(theta = 360 – 120 = 240°)
= (frac{240}{360} times pi times 12)
= (8pi cm^{2})