A cone with the sector angle of 45° is cut out of a circle of radius r of the cone.

A.
(frac{r}{16}) cm 
B.
(frac{r}{6}) cm 
C.
(frac{r}{8}) cm 
D.
(frac{r}{2}) cm
Correct Answer: Option C
Explanation
The formula for the base radius of a cone formed from the sector of a circle = (frac{r theta}{360°})
= (frac{r times 45°}{360°})
= (frac{r}{8} cm)