A cone with the sector angle of 45° is cut out of a circle of radius r of the cone.
-
A.
(frac{r}{16}) cm -
B.
(frac{r}{6}) cm -
C.
(frac{r}{8}) cm -
D.
(frac{r}{2}) cm
Correct Answer: Option C
Explanation
The formula for the base radius of a cone formed from the sector of a circle = (frac{r theta}{360°})
= (frac{r times 45°}{360°})
= (frac{r}{8} cm)