A fair die is tossed once, what is the probability of obtaining neither 5 or 2
-
A.
(frac{5}{6}) -
B.
(frac{2}{3}) -
C.
(frac{1}{2}) -
D.
(frac{1}{6})
Correct Answer: Option B
Explanation
Probability of obtaining a 5 is P(5)=(frac{1}{6})
Probability of obtaining a 2 is P(2)=(frac{1}{6})
Probability of obatining either 2 or 5 = P(2∪5) = (frac{2}{6})
Probability of obtaining neither 5 or 2 = (1 – frac{2}{6}=frac{4}{6}=frac{2}{3})