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A man is four times as old as his son. The difference between their ages…

A man is four times as old as his son. The difference between their ages is 36 years Find the sum of their ages
  • A.
    45 years
  • B.
    48 years
  • C.
    60 years
  • D.
    74 years
Correct Answer: Option C
Explanation

Let the sons age be x. The father is 4x
∴ 4x – x = 36; 3x = 36; x = 12
The son is 12 years and the father is 12 x 4 = 48.
The sum of their ages (12 + 48) years = 60years