A number is selected at random between 10 and 20, both numbers inclusive. Find the probability that the number is an even number
-
A.
(frac{5}{11}) -
B.
(frac{1}{2}) -
C.
(frac{6}{11}) -
D.
(frac{7}{10})
Correct Answer: Option C
Explanation
n(even numbers between 10 and 20 inclusive) = 6
n(numbers between 10 and 20) = 11
P(even) = (frac{6}{11})