A student measures a piece of rope and found that it was 1.26m long. If the actual length of the rope was 1.25m, what was the percentage error in the measurement?
-
A.
0.25% -
B.
0.01% -
C.
0.80% -
D.
0.40%
Correct Answer: Option C
Explanation
Actual length of rope = 1.25mMeasured length of rope = 1.26merror = (1.26 – 1.25)m – 0.01mPercentage error = (frac{error}{text{actual length}}) x 100%= (frac{0.01}{1.25}) x 100% = 0.08%