A student sitting on a tower 68 metres high observes his principal’s car at the angle of depression of 20

^{o}. How far is the car from the bottom of the tower to the nearest metre?-
**A.**

184m -
**B.**

185m -
**C.**

186m -
**D.**

187m

##### Correct Answer: Option D

##### Explanation

Tan 20^{o} = (frac{68m}{x})

x tan 20^{o} = 68

x = (frac{68}{tan 20}) = (frac{68}{0.364})

x = 186.8

= 187m