An arc of circle of radius 2cm subtends an angle of 60

^{o}at the centre. Find the area of the sector-
**A.**

(frac{2 pi}{3})cm^{2} -
**B.**

(frac{pi}{2})cm^{2} -
**C.**

(frac{pi}{3})cm^{2} -
**D.**

(pi)cm^{2}

##### Correct Answer: Option A

##### Explanation

Area of a sector (frac{theta}{360}) x 2(pi)r

= (frac{60^o}{360^o}) x 2(pi)r

= (frac{2 pi}{3})cm^{2}