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# An Unbiased Coin Is Tossed Eight Times What Is the Probability of Getting Less Than 4 Heads

An unbiased coin is tossed eight times what is the probability of getting less than 4 heads.

$$\frac{1}{64}$$
So, the required probability is = $$(\frac{1}{2})^8 + (\frac{1}{2})^8 + (\frac{1}{2})^8 + (\frac{1}{2})^8 = 4(\frac{1}{2})^8 = \frac{1}{2^6} = \frac{1}{64}$$