At what value of x is the function x(^2) + x + 1 minimum?
-
A.
-1 -
B.
(-frac{1}{2}) -
C.
(frac{1}{2}) -
D.
1
Correct Answer: Option B
Explanation
x(^2) + x + 1
(frac{dy}{dx}) = 2x + 1
At the turning point, (frac{dy}{dx}) = 0
2x + 1 = 0
x = -(frac{1}{2})