Home » (begin{array}{c|c} x & 1 & 2 & 3 & 4 & 5 \ hline f…

(begin{array}{c|c} x & 1 & 2 & 3 & 4 & 5 \ hline f…

(begin{array}{c|c} x & 1 & 2 & 3 & 4 & 5 \ hline f & y + 2 & y – 2 & 2y – 3 & y + 4 & 3y – 4end{array})
This table shows the frequency distribution of a data if the mean is (frac{43}{14}) find y

  • A.
    1
  • B.
    2
  • C.
    3
  • D.
    4
Correct Answer: Option B
Explanation
x 1 2 3 4 5 Total
f y + 2 y – 1 2y – 3 y + 4 3y – 4 8y – 2
fx y + 2 2y – 2 6y – 9 4y + 16 15y – 20 28y – 13

Mean = (frac{sum fx}{sum f})

(therefore frac{28y – 13}{8y – 2} = frac{43}{14})

(implies 14(28y – 13) = 43(8y – 2))

(392y – 182 = 344y – 86)

(392y – 344y = -86 + 182 implies 48y = 96)

(y = 2)

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