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(begin{vmatrix} -2 & 1 & 1 \ 2 & 1 & k \1 & 3…

(begin{vmatrix} -2 & 1 & 1 \ 2 & 1 & k \1 & 3 & -1 end{vmatrix}) = 23
  • A.
    1
  • B.
    2
  • C.
    3
  • D.
    4
Correct Answer: Option B
Explanation

-2(-1 – 3k) – 1(-2 -k) + 1(6 – 1) = 23
7k = 14
k = 2

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