(begin{vmatrix} -2 & 1 & 1 \ 2 & 1 & k \1 & 3 & -1 end{vmatrix}) = 23
-
A.
1 -
B.
2 -
C.
3 -
D.
4
Correct Answer: Option B
Explanation
-2(-1 – 3k) – 1(-2 -k) + 1(6 – 1) = 23
7k = 14
k = 2
-2(-1 – 3k) – 1(-2 -k) + 1(6 – 1) = 23
7k = 14
k = 2