Calculate the length in cm. of the area of a circle of diameter 8cm which subtends an angle of 22(frac{1}{2})

^{o}at the centre of the circle-
**A.**

2(pi) -
**B.**

(pi) -
**C.**

(frac{2}{3}) -
**D.**

(frac{pi}{2})

##### Correct Answer: Option D

##### Explanation

Diameter = 8cm

∴ Radius = 4cm

Length of arc = (frac{theta}{360}) x 2 (pi)r but Q = 22(frac{1}{2})

∴ Length (frac{22frac{1}{2}}{360}) x 2 x (pi) x 4

= (frac{22frac{1}{2} times 8pi}{360})

= (frac{180}{360})

= (frac{pi}{2})