Calculate the length in cm. of the area of a circle of diameter 8cm which subtends an angle of 22(frac{1}{2})o at the centre of the circle
-
A.
2(pi) -
B.
(pi) -
C.
(frac{2}{3}) -
D.
(frac{pi}{2})
Correct Answer: Option D
Explanation
Diameter = 8cm
∴ Radius = 4cm
Length of arc = (frac{theta}{360}) x 2 (pi)r but Q = 22(frac{1}{2})
∴ Length (frac{22frac{1}{2}}{360}) x 2 x (pi) x 4
= (frac{22frac{1}{2} times 8pi}{360})
= (frac{180}{360})
= (frac{pi}{2})