Evaluate (frac{x^2 + x – 2}{2x^2 + x -3}) when x = -1

Evaluate (frac{x^2 + x – 2}{2x^2 + x -3}) when x = -1

Correct Answer: Option D

Explanation

(frac{x^2 + x – 2}{2x^2 + x – 3})

= (frac{x^2 + 2x – x – 2}{2x^2 + 3x – 2x – 3})

= (frac{x(x + 2) – 1(x + 2)}{x(2x + 3) – 1(2x + 3)})

= (frac{(x – 1)(x + 2)}{(x – 1)(2x + 3)})

= (frac{x + 2}{2x + 3})

At x = -1, 

= (frac{-1 + 2}{2(-1) + 3})

= (frac{1}{1})

= 1