Evaluate (int sin 2x dx)
-
A.
cos 2x + k -
B.
(frac{1}{2})cos 2x + k -
C.
(-frac{1}{2})cos 2x + k -
D.
-cos 2x + k
Correct Answer: Option C
Explanation
(int sin 2x dx = frac{1}{2} (-cos 2x) + k)
(- frac{1}{2} cos 2x + k)
There is an explanation video available below.