Evaluate ∫(^{pi}_{2})(sec2 x – tan2x)dx
-
A.
(frac{pi}{2}) -
B.
(pi) – 2 -
C.
(frac{pi}{3}) -
D.
(pi) + 2
Correct Answer: Option B
Explanation
∫(^{pi}_{2})(sec2 x – tan2x)dx
∫(^{pi}_{2}) dx = [X](^{pi}_{2})
= (pi) – 2 + c
when c is an arbitrary constant of integration