Find all real numbers x which satisfy the inequality (frac{1}{3})(x + 1) – 1 > (frac{1}{5})(x + 4)
-
A.
x -
B.
x -
C.
x > 6 -
D.
x > 11
Correct Answer: Option D
Explanation
(frac{1}{3})(x + 1) – 1 > (frac{1}{5})(x + 4)
= (frac{x + 1}{3}) – 1 > (frac{x + 4}{5})
(frac{x + 1}{3}) – (frac{x + 4}{5}) – 1 > 0
= (frac{5x + 5 – 3x – 12}{15})
= 2x – 7 > 15
= 2x > 22
= x > 11