Find n if log(_{2}) 4 + log(_{2}) 7 – log(_{2}) n = 1

Find n if log(_{2}) 4 + log(_{2}) 7 – log(_{2}) n = 1

Correct Answer: Option B

Explanation

log(_2) 4 + log(_2) 7 – log(_2) n = 1

= log(_2) (4 x 7) – log(_2) n = 1

(therefore) log(_2) 28 – log(_2) n = 1

= (frac{28}{n} = 2^1)

(frac{28}{n}) = 2

2n = 28

∴ n = 14