Find the acute angle between the straight lines y = x and y = √3x

Find the acute angle between the straight lines y = x and y = √3x

Correct Answer: Option A

Explanation

y = x, Gradient (m₁) = 1
y = √3x gradient (m₂) = √3
(tantheta = frac{m_2 – m_1}{1+m_2 m_1}\
tantheta = frac{sqrt{3}-1}{1+sqrt{3}times 1}\
=frac{1.73 -1 }{1+1.73}=
frac{0.73}{2.73}=0.268)
θ = Tan^-1 (0.268)
= 15^o