Find the eleventh term of the progression 4, 8, 16…..

Find the eleventh term of the progression 4, 8, 16…..

Correct Answer: Option B

Explanation

a = 4, r = (frac{4}{2})
(frac{8}{4}) = 2
n = 11
T_n = ar^{n – 1}
T₁₁ = 4(2)^{11 – 1}
4(2)¹⁰ = 2¹²
since 4 = 2²
= 2¹²