Find the eleventh term of the progression 4, 8, 16…..

A.
2^{13} 
B.
2^{12} 
C.
2^{11} 
D.
2^{10}
Correct Answer: Option B
Explanation
a = 4, r = (frac{4}{2})
(frac{8}{4}) = 2
n = 11
T_{n} = ar^{n – 1}
T_{11} = 4(2)^{11 – 1}
4(2)^{10} = 2^{12}
since 4 = 2^{2}
= 2^{12}