Find the equation of the tangent at the point (2, 0) to the curve y…

Find the equation of the tangent at the point (2, 0) to the curve y = x(^2) – 2x

Correct Answer: Option A

Explanation

The gradient to the curve is found by differentiating the curve equation with respect to x

  So (frac{dy}{dx}) 2x – 2

  The gradient of the curve is the same with that of the tangent.

  At point (2, 0) (frac{dy}{dx}) = 2(2) – 2

  = 4 – 2 = 2

  The equation of the tangent is given by (y – y1) (frac{dy}{dx}) (x – x1)

  At point (x1, y1) = (2, 0)

  y – 0 = 2(x – 2)

  y = 2x – 4

There is an explanation video available below.