Find the equation whose roots are 2 and (3frac{1}{2})

A.
2x^{2} + 3x + 14 = 0 
B.
2x^{2} + 5x + 7 = 0 
C.
2x^{2} + 5x – 7 = 0 
D.
2x^{2} + 3x – 14 = 0
Correct Answer: Option D
Explanation
x^{2} (sum of roots)x + (product of roots) = 0
Sum of roots (2+3frac{1}{2} = 1frac{1}{2}=frac{1}{2})
Product of roots (=2 times 3frac{1}{2}=7\
x^2left(frac{3}{2}right)x+(7)=0Rightarrow 2x^2 + 3x – 14 = 0)