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Find the equation whose roots are 2 and (-3frac{1}{2})

Find the equation whose roots are 2 and (-3frac{1}{2})
  • A.
    2x2 + 3x + 14 = 0
  • B.
    2x2 + 5x + 7 = 0
  • C.
    2x2 + 5x – 7 = 0
  • D.
    2x2 + 3x – 14 = 0
Correct Answer: Option D
Explanation

x2 (sum of roots)x + (product of roots) = 0
Sum of roots (2+-3frac{1}{2} = -1frac{1}{2}=-frac{1}{2})
Product of roots (=2 times -3frac{1}{2}=-7\
x^2-left(frac{-3}{2}right)x+(-7)=0Rightarrow 2x^2 + 3x – 14 = 0)