Find the sum to infinity to the following series 3 + 2 + (frac{4}{3}) + (frac{8}{9}) + (frac{16}{17}) + …..

A.
1270 
B.
190 
C.
18 
D.
9
Correct Answer: Option D
Explanation
3 + 2 + (frac{4}{3}) + (frac{8}{9}) + (frac{16}{17}) + …..
a = 3
r = (frac{2}{3})
s (alpha) = (frac{a}{1 – r}) = (frac{3}{1 – frac{2}{3}})
= (frac{3}{frac{1}{3}})
= 3 x 3
= 9