Find the value of t if the standard deviation of 2t, 3t, 4t, 5t, and 6t is √2
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A.
1 -
B.
2 -
C.
3 -
D.
4
Correct Answer: Option A
Explanation
(mean(x) = frac{20t}{5} = 4t\standardhspace{1mm}deviation=sqrt{frac{10t^2}{5}}\sqrt{2}=sqrt{frac{10t^2}{5}}\sqrt{2}=sqrt{2t^2}\2 = 2t^2\t^2=1\t=1)