Find the values of p for which the equation x

^{2}– (p – 2)x + 2p + 1 = 0-
**A.**

(21, 0) -
**B.**

(0, 12) -
**C.**

(1, 2) -
**D.**

(3, 4) -
**E.**

(4, 5)

##### Correct Answer: Option B

##### Explanation

Equal roots implies b^{2} – 4ac = 0

a = 1b = – (p – 2), c = 2p + 1

[-(p – 2)]^{2} – 4 x 1 x (2p + 1) = 0

p^{2} – 4p + 4 – 4(2p + 1) = 0

p^{2} – 4p = 4 – 8p – 4 = 0

p^{2} – 12p = 0

p(p – 12) = 0

p = 0 or 12