For what value of x does 6 sin (2x – 25)

^{o}attain its maximum value in the range 0^{o}(leq) x (leq) 180^{o}-
**A.**

12(frac{1}{2}) -
**B.**

32(frac{1}{2}) -
**C.**

57(frac{1}{2}) -
**D.**

147(frac{1}{2})

##### Correct Answer: Option C

##### Explanation

y = 6 sin (2x – 25)^{o}

(frac{dy}{dx}) = -12 cos(2x – 25^{o})

(frac{dy}{dx}) = 0

-12 cos x (2x – 25^{o}) = 0

= cos(2x – 25^{o}) = 0

= 2x – 25^{o} = cos^{-1}(0)

= 2x – 25^{o}

= 90^{o}

x = (frac{115}{2})