For what value of x does 6 sin (2x – 25)o attain its maximum value…

For what value of x does 6 sin (2x – 25)^o attain its maximum value in the range 0^o (leq) x (leq) 180^o

Correct Answer: Option C

Explanation

y = 6 sin (2x – 25)^o
(frac{dy}{dx}) = -12 cos(2x – 25^o)
(frac{dy}{dx}) = 0
-12 cos x (2x – 25^o) = 0
= cos(2x – 25^o) = 0
= 2x – 25^o = cos^-1(0)
= 2x – 25^o
= 90^o
x = (frac{115}{2})