From a point Z, 60 m north of X, a man walks 60√3m eastwards to another point Y. Find the bearing of Y from X.

A.
0.30^{o} 
B.
045^{o} 
C.
060^{o} 
D.
090^{o}
Correct Answer: Option C
Explanation
tan (theta) = (frac{60sqrt{3}}{60}) = (sqrt{3})
(theta) = tan (frac{1}{3}) = 60^{o}
Bearing of y from x = 060^{o}