From a set (A = [3, sqrt{2}, 2sqrt{3}, sqrt{9}, sqrt{7}]), a number is selected at random. Find the probability that is a rational number
-
A.
(frac{1}{5}) -
B.
(frac{2}{5}) -
C.
(frac{3}{5}) -
D.
(frac{4}{5})
Correct Answer: Option B
Explanation
(A = {3, sqrt{2}, 2sqrt{3}, sqrt{9}, sqrt{7}})
n(A) = 5
Let the rational nos = R
n(R) = 2 (3, (sqrt{9}))
P(R) = 2/5