From the figure, calculate TH in centimeters
-
A.
(frac{5}{sqrt{3} + 1}) -
B.
(frac{5}{sqrt{3} – 1}) -
C.
(frac{5}{sqrt{3}}) -
D.
(frac{sqrt{3}}{5})
Correct Answer: Option B
Explanation
TH = tan 45o, TH = QH
(frac{TH}{5 + QH}) = tan 30o
TH = (b + QH) tan 30o
QH = 56 (5 + QH) (frac{1}{sqrt{3}})
QH(1 – (frac{1}{sqrt{3}})) = (frac{5}{sqrt{3}})
QH = (frac{5sqrt{3}}{sqrt{3}} – frac{1}{sqrt{3}})
= (frac{5}{sqrt{3} – 1})