Given that 3x – 5y – 3 = 0, 2y – 6x + 5 = 0 the value of (x, y) is
-
A.
((frac{-1}{8}, frac{19}{24})) -
B.
8, (frac{24}{19}) -
C.
-8, (frac{24}{19}) -
D.
((frac{19}{24}, frac{-1}{8}))
Correct Answer: Option D
Explanation
3x – 5y = 3, 2y – 6x = -5
-5y + 3x = 3……..{i} x 2
2y – 6x = -5………{ii} x 5
Substituting for x in equation (i)
-5y + 3((frac{19}{24})) = 3
-5y + 3 x (frac{19}{24}) = 3
-5y = (frac{3 – 19}{8})
-5 = (frac{24 – 19}{8})
= (frac{5}{8})
y = (frac{5}{8 times 5})
y = (frac{-1}{8})
(x, y) = ((frac{19}{24}, frac{-1}{8})