Home » Given that sin (5x – 28)o = cos (3x – 50)o,0 Given that sin (5x – 28)o = cos (3x – 50)o,0 o, find the value of x

Given that sin (5x – 28)o = cos (3x – 50)o,0 Given that sin (5x – 28)o = cos (3x – 50)o,0 o, find the value of x

Given that sin (5x – 28)^o = cos (3x – 50)^o,0 o, find the value of x

A. 14^o
B. 21^o
C. 32^o
D. 39^o

Correct Answer: Option B

Explanation

Sin (5x – 28)^o = cos (3x – 50)^o
Since by the trigonometry relation
Sin(5x – 28)^o = cos[90 – (5x – 28)]^o
Hence cos(3x – 50)^o = cos[90 – (5x – 28)]^o
3x – 50 = 90 – (5x-28)
3x – 50 = 90 – 5x + 28
3x + 5x = 90 + 28 + 50
8x = 168
(x = frac{168}{8}=21^{circ})