Given that the root of an the equation (2x^2 + (k+2)x+k=0) is 2, find the value of k
-
A.
-4 -
B.
-2 -
C.
-1 -
D.
(-frac{1}{4})
Correct Answer: Option A
Explanation
Substituting for x in the equation
(2(2)^2 + (k+2)2+k = 0 Rightarrow 8 +2k + 4 + k =0 Rightarrow 3k =-12; k=-4)