If 2log3 y + log3 x2 = 4, then y is
-
A.
4 – log3 -
B.
(frac{4}{log_3 x}) -
C.
(frac{4}{x}) -
D.
(pm) (frac{9}{x})
Correct Answer: Option D
Explanation
2log3y + log3x2 = 4
log3y2 + log3x2 = 4
∴ log3 (x2y2) = log381(correct all to base 4)
x2y2 = 81
∴ xy = (pm)9
∴ y = (pm)(frac{9}{x})