If (3x – frac{1}{4})^{frac{1}{2}} > frac{1}{4} – x ), then the interval of values of x is
-
A.
x > (frac{1}{3}) -
B.
x -
C.
x -
D.
x -
E.
x > (frac{9}{16})
Correct Answer: Option E
Explanation
(3x – (frac{1}{4})^{-frac{1}{2}} > frac{1}{4} – x)
= (3x – 4^{frac{1}{2}} > frac{1}{4} – x)
= (3x – 2 > frac{1}{4} – x)
= (3x + x > frac{1}{4} + 2 implies 4x > frac{9}{4})
(x > frac{9}{16})