If (4sin^2 x – 3 = 0), find the value of x, when 0° (leq) x (leq) 90°
-
A.
90° -
B.
45° -
C.
60° -
D.
30°
Correct Answer: Option C
Explanation
(4sin^2 x – 3 = 0)
(4 sin^2 x = 3 implies sin^2 x = frac{3}{4})
(sin x = frac{sqrt{3}}{2})
(therefore x = sin^{-1} (frac{sqrt{3}}{2}))
x = 60°
There is an explanation video available below.