If (8^{x+1}=frac{1}{4}), find x
-
A.
(-frac{5}{3}) -
B.
-1 -
C.
(-frac{1}{3}) -
D.
(frac{1}{3})
Correct Answer: Option A
Explanation
(8^{x+1}=frac{1}{4}\
2^{3(x+1)}=2^{-2}Rightarrow 3(x+1)=-2Rightarrow 3x+3=-2\
3x=-5Rightarrow x=frac{5}{3})
(8^{x+1}=frac{1}{4}\
2^{3(x+1)}=2^{-2}Rightarrow 3(x+1)=-2Rightarrow 3x+3=-2\
3x=-5Rightarrow x=frac{5}{3})