-
A.
120(pi)cm3 -
B.
110(pi)cm3 -
C.
60(pi)cm3 -
D.
50(pi)cm3
Correct Answer: Option B
Explanation
The volume of the pipe is equal to the area of the cross section and length.
let outer and inner radii be R and r respectively.
Area of the cross section = (R2 – r2)
where R = 6 and r = 6 – 1
= 5cm
Area of the cross section = (62 – 52)(pi) = (36 – 25)(pi)cm sq
vol. of the pipe = (pi) (R2 – r2)L where length (L) = 10
volume = 11(pi) x 10
= 110(pi)cm3