If a u

^{2}– 3v^{2}and b = 2uv + v^{2}evaluate (2a – b)(a – b^{2}), when u = 1 and v = -1-
**A.**

9 -
**B.**

15 -
**C.**

27 -
**D.**

33

##### Correct Answer: Option A

##### Explanation

a = u^{2} – 3y^{2} = (1)^{2} – 3(-1) = -2

b = 2uu + v^{2} + v^{2}

= 2(1)(-1) + (-1)^{2} = -1

∴ 2(2a – b)(a – b∴) = [2(-2) – 1](-2 – (-1)2)

= -3 – 3

= 9