If a u2 – 3v2 and b = 2uv + v2 evaluate (2a – b)(a…

If a u² – 3v² and b = 2uv + v² evaluate (2a – b)(a – b²), when u = 1 and v = -1

Correct Answer: Option A

Explanation

a = u² – 3y² = (1)² – 3(-1) = -2
b = 2uu + v² + v²
= 2(1)(-1) + (-1)² = -1
∴ 2(2a – b)(a – b∴) = [2(-2) – 1](-2 – (-1)2)
= -3 – 3
= 9