If a

^{2}+ b^{2}= 16 and 2ab = 7.Find all the possible values of (a – b)-
**A.**

3, -3 -
**B.**

2, -2 -
**C.**

1, -1 -
**D.**

3, -1

##### Correct Answer: Option A

##### Explanation

a^{2} + b^{2} = 16 and 2ab = 7

To find all possible values = (a – b)^{2} + b^{2} – 2ab

Substituting the given values = (a – b)^{2}

= 16 – 7

= 9

(a – b) = (pm)9

= (pm)3

OR a – b = 3, -3