If cos(theta) = (frac{a}{b}), find 1 + tan

^{2}(theta)-
**A.**

(frac{b^2}{a^2}) -
**B.**

(frac{a^2}{b^2}) -
**C.**

(frac{a^2 + b^2}{b^2 – a^2}) -
**D.**

(frac{2a^2 + b^2}{a^2 + b^2})

##### Correct Answer: Option A

##### Explanation

cos(theta) = (frac{a}{b}), Sin(theta) = (sqrt{frac{b^2 – a^2}{a}})

Tan(theta) = (sqrt{frac{b^2 – a^2}{a^2}}), Tan ^{2} = (sqrt{frac{b^2 – a^2}{a^2}})

1 + tan^{2}(theta) = 1 + (frac{b^2 – a^2}{a^2})

= (frac{a^2 + b^2 – a^2}{a^2})

= (frac{b^2}{a^2})