If P = (begin{pmatrix} 2 & -3 \ 1 & 1 end{pmatrix})
-
A.
(begin{pmatrix} -{frac{1}{5}} & -{frac{3}{5}} \ -{frac{1}{5}} & -{frac{2}{5}} end{pmatrix}) -
B.
(begin{pmatrix} {frac{1}{5}} & {frac{3}{5}} \ {frac{1}{5}} & {frac{2}{5}} end{pmatrix}) -
C.
(begin{pmatrix} -{frac{1}{5}} & {frac{3}{5}} \ -{frac{1}{5}} & {frac{2}{5}} end{pmatrix}) -
D.
(begin{pmatrix} {frac{1}{5}} & {frac{3}{5}} \ -{frac{1}{5}} & {frac{2}{5}} end{pmatrix})
Correct Answer: Option D
Explanation
P = (begin{pmatrix} 2 & -3 \ 1 & 1 end{pmatrix})
|P| = 2 – 1 x -3 = 5
P-1 = (frac{1}{5})(begin{pmatrix} 1 & 3 \ -1 & 2 end{pmatrix})
= (begin{pmatrix} {frac{1}{5}} & {frac{3}{5}} \ -{frac{1}{5}} & {frac{2}{5}} end{pmatrix})