If p varies inversely as the square of q and p=8 when q=4, find q when p =32
-
A.
(pm)16 -
B.
(pm)8 -
C.
(pm)4 -
D.
(pm)2
Correct Answer: Option D
Explanation
p ∝ 1/q
p = k/q
K = q(^2)p
= 4(^2)(8)
∴p = 128/q
32 = 128/q
q(^2) = 128/32
q(^2) = 4
q = √4 = (pm) 2