Home » If tan (theta) = (frac{m^2 – n^2}{2mn}) find sec(theta)

If tan (theta) = (frac{m^2 – n^2}{2mn}) find sec(theta)

If tan (theta) = (frac{m^2 – n^2}{2mn}) find sec(theta)
  • A.
    (frac{m^2 + n^2}{(m^2 – n^2)})
  • B.
    (frac{m^2 + n^2}{2mn})
  • C.
    (frac{mn}{2(m^2 + n^2)})
  • D.
    (frac{m^2n^2}{2(m^2 – n^2)})
Correct Answer: Option B
Explanation

Tan (theta) = (frac{m^2 – n^2}{2mn})
(frac{text{Opp}}{text{Adj}}) by pathagoras theorem
= Hyp2 = Opp2 + Adj2
Hyp2 = (m2 – n2) + (2mn)2
Hyp2 = m4 – 2m2n4 – 4m2 – n2
Hyp2 = m4 + 2m2 + n2n
Hyp2 = (m2 – n2)2
Hyp2 = (frac{m^2 + n^2}{2mn})

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